1/n(n+2)(n+4)=1/4[1/n(n+2)-1/(n+2)(n+4)]
∴原式=1/4*(1/11*13-1/13*15+1/13*15-1/15*17+……+1/29*31-1/31*33)
=1/4*(1/11*13-1/31*33)
=1/4*(80/13*31*33)
=20/13299
1/(11*13*15)+1/(13*15*17)+.+1/(29*31*33)=
1/(11*13*15)+1/(13*15*17)+.+1/(29*31*33)=
數(shù)學(xué)人氣：754 ℃時(shí)間：2020-04-18 03:52:42
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