設(shè) y = ax² + bx + c
因為f(0) = 1
所以 c = 1
因為f(x+1)-f(x)=2x,
所以 ax² + 2ax + a + bx + b + 1 - ax² - bx - 1 = 2x
化簡得：2ax + a + b = 2x
所以 a = 1 , b = -1
所以f(x) = x² - x + 1
f(x) = x² - x + 1
=(x - 1/2)² + 3/4
當(dāng) x = 1/2 時
fmin = f(1/2) = 3/4