求函數(shù)的極限:lim(1^n+2^n+3^n+4^n)^1/n,當(dāng)n→∞時(shí)的極限.(不用夾逼準(zhǔn)則解)
求函數(shù)的極限:lim(1^n+2^n+3^n+4^n)^1/n,當(dāng)n→∞時(shí)的極限.(不用夾逼準(zhǔn)則解)
數(shù)學(xué)人氣:301 ℃時(shí)間:2020-06-14 19:42:11
優(yōu)質(zhì)解答
(1^n+2^n+3^n+4^n)^1/n=e^{ln[(1^n+2^n+3^n+4^n)^1/n]}=e^{(1/n)*ln(1^n+2^n+3^n+4^n)}lim(n->∞) (1/n)*ln(1^n+2^n+3^n+4^n) (用咯比達(dá)法則)=lim(n->∞) [(ln1*1^n+ln2*2^n+ln3*3^n+ln4*4^n)/(1^n+2^n+3^n+4^n)]=...
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