求下列函數(shù)導(dǎo)數(shù) y=cot(1/x)
求下列函數(shù)導(dǎo)數(shù) y=cot(1/x)
求下列函數(shù)導(dǎo)數(shù) y=cot(1/x)
y=x平方sin(1/x)
y=ln［ln（lnx）］
求下列函數(shù)微分
y=lnsin x/2
y=artan 1+x/1-x
求下列函數(shù)導(dǎo)數(shù) y=cot(1/x)
y=x平方sin(1/x)
y=ln［ln（lnx）］
求下列函數(shù)微分
y=lnsin x/2
y=artan 1+x/1-x
數(shù)學(xué)人氣：926 ℃時(shí)間：2020-06-02 18:24:09
優(yōu)質(zhì)解答
∵y=cot(1/x)∴y'=x^(-2)csc^2(1/x)y=x^2sin(1/x)y'=2xsin(1/x)-cos(1/x)y=ln[ln(lnx)]y'=[1/ln(lnx)][ln(lnx)]'={1/[lnxln(lnx)]}(lnx)'=1/[xlnxln(lnx)]y=lnsin(x/2)y'=[1/sin(x/2)][sin(x/2)]'=(1/2)cos(x/2)/sin...
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