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  • x*-2xy+3y*=9 4x*-5xy+6y*=30

    x*-2xy+3y*=9 4x*-5xy+6y*=30
    *指平方由這兩個式子組成的方程組,求x和y的解
    其他人氣:340 ℃時間:2020-02-04 15:15:08
    優(yōu)質(zhì)解答
    Solution:x^2 - 2xy + 3y^2 = 9 (1)
    4x^2 - 5xy + 6y^2 = 30 (2)
    Eq(1)*5 - Eq(2)*2,we have x^2 - y^2 = 5 (3)
    Eq(2) - Eq(1),we get x^2 + y^2 - xy = 7 (4)
    Eq(3) + Eq(4),we obtain x^2 - xy = 12
    Make x subject,x = 2(y - 1/y) (5)
    Sub Eq(5) into Eq(3),4(y^2 - 2 + 1/y^2) - y^2 =5
    Let u = y^2,4(u - 2 + 1/u) - u = 5
    Transposing and Simplifying,3u^2 - 13u + 4 = 0
    Factorizing,then u1 = 4,u2 = 1/3
    Sub u = y^2 into u1 = 4,we find y1 = 2,
    y2 = -2,
    Sub u = y^2 into u1 = 1/3,we find y3 = 1/(square root of 3)
    y4 = -1/(square root of 3)
    Correspondingly,x1 = 3
    x2 = -3
    x3 = -4/(square root of 3)
    x4 = 4/(square root of 3)
    By inspection,we confirm all solutions above are correct.
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