f(x-1)=x^2-2x+1-1=(x-1)^2-1
所以f(x)=x^2-1
令f(x)=2
即x^2-1=2
x=3
因?yàn)閒(x)在(-∞,0)上有反函數(shù)
所以x=-根號(hào)3
即f﹣¹(2)=-根號(hào)3
已知f(x)在(-∞,0)上有反函數(shù),且f(x-1)=x^2-2x,求f﹣¹(2).
已知f(x)在(-∞,0)上有反函數(shù),且f(x-1)=x^2-2x,求f﹣¹(2).
數(shù)學(xué)人氣：412 ℃時(shí)間：2020-05-19 00:25:21
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