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  • 1/(sinx)^m ,不定積分

    1/(sinx)^m ,不定積分
    數(shù)學(xué)人氣:298 ℃時(shí)間:2020-05-28 19:10:42
    優(yōu)質(zhì)解答
    最厚的積分書(shū)都已經(jīng)查了,非整數(shù)不存在公式!
    整數(shù)m 則是逐一可解的:
    m=1,-(log(cos(x)+1)-log(cos(x)-1))/2
    m=2,-1/tan(x)
    m=3,-((cos(x)^2-1)*log(cos(x)+1)+(1-cos(x)^2)*log(cos(x)-1)-2*cos(x))/(4*cos(x)^2-4)
    m=4,-(3*tan(x)^2+1)/(3*tan(x)^3).
    m=5,-(3*sin(x)^4*log(cos(x)+1)-3*sin(x)^4*log(cos(x)-1)+6*cos(x)*sin(x)^2+4*cos(x))/(16*sin(x)^4)
    m=6,-(8*cos(x)^5-20*cos(x)^3+15*cos(x))/(15*sin(x)^5)
    m=7,-(15*sin(x)^6*log(cos(x)+1)-15*sin(x)^6*log(cos(x)-1)+30*cos(x)*sin(x)^4+20*cos(x)*sin(x)^2+16*cos(x))/(96*sin(x)^6)
    m=8,(16*cos(x)^7-56*cos(x)^5+70*cos(x)^3-35*cos(x))/(35*sin(x)^7)
    m=9,-(105*sin(x)^8*log(cos(x)+1)-105*sin(x)^8*log(cos(x)-1)+210*cos(x)*sin(x)^6+140*cos(x)*
    sin(x)^4+112*cos(x)*sin(x)^2+96*cos(x))/(768*sin(x)^8)
    m=10,-(128*cos(x)^9-576*cos(x)^7+1008*cos(x)^5-840*cos(x)^3+315*cos(x))/(315*sin(x)^9)
    ...
    但也不存在簡(jiǎn)易的一般公式!
    我來(lái)回答
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