如圖所示,AC平分∠DAB,AB>AD,CB=CD,CE⊥AB于E, (1)求證:AB=AD+2EB; (2)若AD=9,AB=21,BC=10,求AC的長(zhǎng).
如圖所示,AC平分∠DAB,AB>AD,CB=CD,CE⊥AB于E,
![](http://hiphotos.baidu.com/zhidao/pic/item/0ff41bd5ad6eddc41160154a3adbb6fd536633ff.jpg)
(1)求證:AB=AD+2EB;
(2)若AD=9,AB=21,BC=10,求AC的長(zhǎng).
![](http://hiphotos.baidu.com/zhidao/pic/item/0ff41bd5ad6eddc41160154a3adbb6fd536633ff.jpg)
(1)求證:AB=AD+2EB;
(2)若AD=9,AB=21,BC=10,求AC的長(zhǎng).
數(shù)學(xué)人氣:198 ℃時(shí)間:2020-03-05 17:59:44
優(yōu)質(zhì)解答
(1)證明:延長(zhǎng)線段AD,過(guò)C作CF⊥AD交AD得延長(zhǎng)線于F,∵AC為∠DAE的平分線,CE⊥AB,CF⊥AF,∴CE=CF,在Rt△CFD和Rt△CEB中CF=CECD=CB,∴Rt△CFD≌Rt△CEB(HL),∴FD=EB,又在Rt△CFA和Rt△CEA中CF=CEAC=AC...
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