求導(dǎo),f‘(x)
由題意可知:f‘(1)=0
解不等式組,得出a的取值范圍.
由于擔(dān)心對題的理解有誤,我就只告訴你方法,你自己去做.
已知函數(shù)f(x)=1/3x立方-1/2ax平方+(a+1)x+1在區(qū)間(1,4)上為減函數(shù),在區(qū)間(6,正無窮大)上為增函數(shù),求實數(shù)a的取值范圍
已知函數(shù)f(x)=1/3x立方-1/2ax平方+(a+1)x+1在區(qū)間(1,4)上為減函數(shù),在區(qū)間(6,正無窮大)上為增函數(shù),求實數(shù)a的取值范圍
數(shù)學(xué)人氣:593 ℃時間:2019-09-03 11:43:32
優(yōu)質(zhì)解答
我來回答
類似推薦
- 設(shè)函數(shù)f(x)=-1/3x立方+2ax平方-3a平方x+1.0
- 設(shè)函數(shù)f(x)=-1/3x立方+2ax平方-3a平方x+1.0
- 已知函數(shù)fx=2ax立方-3x平方,a>0
- 設(shè)函數(shù)F(X)=2/3X三次方+1/2AX平方+X 若F(x)在(0;正無窮)內(nèi)為增函數(shù),求A的取值的范圍.
- 設(shè)函數(shù)f(x)=-3x的平方-2ax+1 x屬于[-1/3,1/3]求f(x)的值域
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()