x的絕對(duì)值為√7 ====》x²=7
實(shí)數(shù)a、b互為相反數(shù) ====》(a+b)=0 ,a=-b
√ab 是個(gè)虛數(shù)
c、d互為倒數(shù) ====》cd=1
x²+(a+b)+x+√ab
=7+0+x+√ab
=7+x+√ab
√ab 是個(gè)虛數(shù) 題目錯(cuò)了吧 如果是√cd =1
x可能是√7 也可能是-√7
所以可能是7+√7+√ab或者7-√7+√ab
實(shí)數(shù)a、b互為相反數(shù),c、d互為倒數(shù),x的絕對(duì)值為√7,求代數(shù)式x²+(a+b)+x+√ab的
實(shí)數(shù)a、b互為相反數(shù),c、d互為倒數(shù),x的絕對(duì)值為√7,求代數(shù)式x²+(a+b)+x+√ab的
實(shí)數(shù)a、b互為相反數(shù),c、d互為倒數(shù),x的絕對(duì)值為√7,求代數(shù)式x²+(a+b)+x+√ab的值為
實(shí)數(shù)a、b互為相反數(shù),c、d互為倒數(shù),x的絕對(duì)值為√7,求代數(shù)式x²+(a+b)+x+√ab的值為
數(shù)學(xué)人氣：284 ℃時(shí)間：2019-08-20 13:10:01
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