已知函數(shù)f(x)等于x^3加ax^2加3/2x加3/2a,且f'(-1)等于0 求a的值 求函數(shù)f(x)在〔-1,0〕上的最值
已知函數(shù)f(x)等于x^3加ax^2加3/2x加3/2a,且f'(-1)等于0 求a的值 求函數(shù)f(x)在〔-1,0〕上的最值
數(shù)學(xué)人氣：556 ℃時(shí)間：2020-04-08 19:32:39
優(yōu)質(zhì)解答
(1)f(x)=x^3+ax^2+（3/2）x+（3/2）af'(x)=3x^2+2ax+3/2f'(-1)=3*(-1)^2+2a*(-1)+3/2=03-2a+3/2=02a=3+3/2=9/2a=9/4f'(x)=3x^2+2*9/4x+3/2=3x^2+9x/2+3/2=3(x^2+3x/2+9/16)-27/16+3/2=3(x+3/4)^2-3/16當(dāng)x=-3/4時(shí)有最...
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