精品偷拍一区二区三区,亚洲精品永久 码,亚洲综合日韩精品欧美国产,亚洲国产日韩a在线亚洲

  • <center id="usuqs"></center>
  • 
    
  • 求證:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos

    求證:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos
    數(shù)學(xué)人氣:891 ℃時(shí)間:2020-01-30 04:06:06
    優(yōu)質(zhì)解答
    sin^2/(sin-cos) - (sin+cos)/(tan^2 -1)
    =sin^2/(sin-cos) -(sin+cos)/[(sin^2/cos^2)-1]
    =sin^2/(sin-cos) -(sin+cos)cos^2/(sin^2-cos^2)
    =sin^2/(sin-cos) -cos^2/(sin-cos)
    (sin^2-cos^2)/(sin-cos)
    =sin-cos
    我來回答
    類似推薦
    請(qǐng)使用1024x768 IE6.0或更高版本瀏覽器瀏覽本站點(diǎn),以保證最佳閱讀效果。本頁提供作業(yè)小助手,一起搜作業(yè)以及作業(yè)好幫手最新版!
    版權(quán)所有 CopyRight © 2012-2024 作業(yè)小助手 All Rights Reserved. 手機(jī)版