由題意可知,粒子軌道半徑:r1=2r2,
由題意可知,穿過鋁板時(shí)粒子動(dòng)能損失一半,即:
1 |
2 |
1 |
2 |
1 |
2 |
2 |
粒子在磁場(chǎng)中做勻速圓周運(yùn)動(dòng),
由牛頓第二定律得:qvB=m
v2 |
r |
磁感應(yīng)強(qiáng)度:B=
mv |
qr |
磁感應(yīng)強(qiáng)度之比:
B1 |
B2 |
| ||
|
v1r2 |
v2r1 |
| ||
v2 |
r2 |
2r2 |
| ||
2 |
故選:D.
2 |
| ||
2 |
1 |
2 |
1 |
2 |
1 |
2 |
2 |
v2 |
r |
mv |
qr |
B1 |
B2 |
| ||
|
v1r2 |
v2r1 |
| ||
v2 |
r2 |
2r2 |
| ||
2 |