(x-10):下雨后C實際用時=(1-
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下雨后C實際用時=(x-10)÷
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下雨后A、B、C實際用時一樣,都是:(x-10)÷
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則下雨后A原定時間:(x-10)÷
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下雨后B原定時間:(x-10)÷
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A、B原定時間相差:
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9x-90=360,
x=50;
答:C車原定行駛?cè)桃?0分鐘.
故答案為:50.
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