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  • 運(yùn)用平方差公式計算: ①40又1/3×39又2/3 ②2014²-2015×293 ③9﹙10+1﹚﹙10²+1﹚+1

    運(yùn)用平方差公式計算: ①40又1/3×39又2/3 ②2014²-2015×293 ③9﹙10+1﹚﹙10²+1﹚+1
    運(yùn)用平方差公式計算:
    ①40又1/3×39又2/3
    ②2014²-2015×293
    ③9﹙10+1﹚﹙10²+1﹚+1
    ④5﹙a-2b﹚﹙1/5a+2/5b﹚
    ⑤﹙﹣3a+b﹚﹙﹣2b+3a﹚+4b²
    ⑥﹙x+y﹚²-﹙x-y﹚²
    ⑦25²-24²
    ⑧﹙1-1/2²﹚﹙1-1/3²﹚﹙1-1/4²﹚...﹙1-1/9²﹚﹙1-1/10²﹚
    ⑨若﹙a+b﹚²=16,﹙a-b﹚²=8,求ab的值
    ⑩計算:﹙﹣a-2b﹚﹙2a-b﹚-﹙a-2b﹚﹙b+2a﹚
    ⑾﹙a+2b﹚﹙a-2b﹚+﹙a+2b﹚²-4ab
    ⑿﹙2x+y+1﹚﹙2x+y-1﹚
    ⒀﹙x-2y﹚﹙x+2y﹚-﹙x+2y﹚²
    ⒁﹙a+b+c﹚²
    ⒂﹙2x-y-1﹚²
    其他人氣:440 ℃時間:2019-12-15 12:22:07
    優(yōu)質(zhì)解答
    原式= (40+1/3)(39+2/3)=(40+1/3)(40-1/3)=1600-1/9
    2014²-2015×293=2014²-2015×293-1+1
    =(2014+1)(2014-1)-2015×293+1
    =2015x2013 -2015×293+1
    =2015(2013-293) + 1 = 2015x1720 + 1
    3、解 9x11x101+1 = 99x101 + 1= (100-1)(100+1) +1 = 10000-1+1 = 10000
    5﹙a-2b﹚﹙1/5a+2/5b﹚=5x1/5 (a - 2b)(a + 2b) =a² - 4b²
    (﹣3a+b﹚﹙﹣2b+3a﹚+4b² = 4b² -(3a-b)(3a-2b)
    = 4b² -(9a²-9ab+2b²)
    =2b² -9a²+9ab
    =(b+3a)(b-3a)+b(b+3a)+6ab
    =(b+3a)(2b-3a)+6ab
    ﹙x+y﹚²-﹙x-y﹚² = (x+y+x-y)(x+y-x+y) = 4xy
    25²-24² =(24+1)²-24² = (24+1+24)(24+1-24) = 49
    ﹙1-1/2²﹚﹙1-1/3²﹚﹙1-1/4²﹚...﹙1-1/9²﹚﹙1-1/10²﹚=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4).(1+1/9)(1-1/9)(1+1/10)(1-1/10)
    =(3/2)(1/2)(4/3)(2/3)(5/4)(3/4).(10/9)(8/9)(11/10)(9/10)
    =[(3/2)(4/3)(5/4)..,(10/9)(11/10)][(1/2)(2/3)(3/4).(8/9)(9/10)]
    =(11/2)(1/10) = 11/20
    ﹙a+b﹚²=16 ,a²+b²+2ab =16 (1)
    ﹙a-b﹚²=8 a²+b²-2ab =8 (2)
    (1) - (2) 得:4ab = 8 解得:ab = 2
    (﹣a-2b)(2a-b)-(a-2b)(b+2a) = (a+2b)(b-2a)-(a-2b)(b+2a)
    =(-2a²-3ab+2b²) - (2a²-3ab-2b²) = 4b²-4a² = 4(b+a)(b-a)
    太晚了,我在替你寫作業(yè)啊!剩下的很簡單,你仿照上面的方法可以做出來的!
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