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  • 幾道因式分解題要求助!

    幾道因式分解題要求助!
    x^4+4x^3-12x-9
    x^3-y^3-x^2-xy-y^2
    a^8+a^4b^4+b^8
    (a^2-1)(b^2-1)-4ab
    麻煩給出過程和思路
    數(shù)學(xué)人氣:921 ℃時間:2020-04-15 21:05:37
    優(yōu)質(zhì)解答
    x^4+4x³-12x-9,補回x²項
    =x^4+4x³+3x²-3x²-12x-9
    =x²(x²+4x+3)-3(x²+4x+3)
    =(x²+4x+3)(x²-3)
    =(x+1)(x+3)(x²-3)
    =(x+1)(x+3)(x+√3)(x-√3)
    x³-y³-x²-xy-y²,補回x²y項和xy²項
    =x³+x²y+xy²-x²y-xy²-y³-x²-xy-y²
    =x(x²+xy+y²)-y(x²+xy+y²)-(x²+xy+y²)
    =(x-y-1)(x²+xy+y²)
    a^8+(a^4)(b^4)+b^8,記得a²+b²=(a+b)²-2ab
    =a^8+2(a^4)(b^4)+b^8-(a^4)(b^4)
    =(a^4+b^4)²-(a²b²)²
    =(a^4+b^4+a²b²)(a^4+b^4-a²b²)
    =(a^4+2a²b²+b^4-a²b²)(a^4-a²b²+b^4)
    =[(a²+b²)²-(ab)²](a^4-a²b²+b^4)
    =(a²+b²-ab)(a²+b²+ab)(a^4-a²b²+b^4)
    (a²-1)(b²-1)-4ab,拆開再重組
    =a²b²-a²-b²-4a²+1
    =a²b²-4ab-a²-b²+1
    =a²b²-2ab+1-a²-2ab-b²
    =a²b²-2ab+1-(a²+2ab+b²)
    =(ab-1)²-(a+b)²
    =[(ab-1)-(a+b)][(ab-1)+(a+b)]
    =(ab-1-a-b)(ab-1+a+b)
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