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  • 已知tana=2,則sin^2a+sina*cosa-2cos^2a=

    已知tana=2,則sin^2a+sina*cosa-2cos^2a=
    數(shù)學(xué)人氣:304 ℃時間:2019-12-07 05:06:27
    優(yōu)質(zhì)解答
    tana = 2
    sin²a = 4/5
    cos²a = 1/5
    sina cosa = 2/5
    sin²a + sina cosa - 2cos²a = 4/5 + 2/5 - 2/5 = 4/5sina,cosa怎么推出來的?求方法tan²a = sin²a / (1 - sin²a) = 4 , sin²a = 4/5cos²a = 1 - sin²a = 1/5(sina cosa)² = sin²a cos²a = 4/25tana = sina / cosa > 0sina cosa > 0sina cosa = 2/5sin²a + sina cosa - 2cos²a = 4/5 + 2/5 - 2/5 = 4/5大神,這里不明白,麻煩再教我一下tan²a = sin²a / (1 - sin²a) = 4tana = sina / cosatan²a = sin²a / cos²a = sin²a / (1 - sin²a)sin²a = tan²t / (1 + tna²t) = 4/5謝謝,大神,你說的我都明白了,可是sin²a = tan²t / (1 + tna²t) = 4/5是不是你打錯了,我怎么弄給出這一步啊應(yīng)該是:sin²a = tan²a / (1 + tna²a) = 4/5 推導(dǎo)過程如下:tana = sina / cosatan²a = sin²a / cos²a = sin²a / (1 - sin²a)tan²a(1 - sin²a) = sin²atan²a - tan²a sin²a = sin²atan²a = (tan²a + 1)sin²asin²a = tan²a / (1 + tan²a)
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