∫xf(x)dx=lnx+c
xf(x) = 1/x
f(x) = 1/x^2
∫f(x)dx = -1/x + C
若∫xf(x)dx=lnx+c,則∫f(x)dx等于多少?
若∫xf(x)dx=lnx+c,則∫f(x)dx等于多少?
數(shù)學(xué)人氣：746 ℃時(shí)間：2020-06-07 13:08:40
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