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倒數(shù)第2行有錯(cuò)誤:
答:
x<=√3,f(x)=1
√3
(-1→2010) ∫ f(x) dx
=(-1→√3) ∫ f(x) dx+(√3→2) ∫ f(x)dx+(2→2010) ∫ f(x)dx
=(-1→√3) ∫ dx+(√3→2)∫ √(4-x^2) dx+0 設(shè)x=2sint
=(√3+1)+(π/3→π/2) ∫ 2cost d(2sint)
=(√3+1)+(π/3→π/2) 2∫ 2(cost)^2 dt
=(√3+1)+(π/3→π/2) 2∫ cos2t+1 dt
=(√3+1)+(π/3→π/2) (sin2t+2t)
=(√3+1)+(0+π)-(√3/2+2π/3)
=√3/2+1+π/3已經(jīng)修改過了,結(jié)果=√3/2+1+π/3
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