∴燈泡正常發(fā)光時(shí)的電壓為6V,功率為3W,
∵P=UI,
∴通過燈泡的電流I=
P額 |
U額 |
3W |
6V |
∵I=
U |
R |
∴燈泡的電阻RL=
U額 |
I |
6V |
0.5A |
(2)若將該燈泡接到電壓為3V的電源上,
∵燈泡的電阻不變,
∴I′=
U′ |
RL |
3V |
12Ω |
此時(shí)燈的實(shí)際功率:
P實(shí)=U′I′=3V×0.25A=0.75W.
故答案為:5;12;0.5;0.25;0.75.
P額 |
U額 |
3W |
6V |
U |
R |
U額 |
I |
6V |
0.5A |
U′ |
RL |
3V |
12Ω |