∵(x+y)2-2x-2y+1=0,
∴(x+y)2-2(x+y)+1=0,
∴(x+y-1)2=0
∴x+y=1.
故答案為1.
已知(x+y)2-2x-2y+1=0,則x+y=_.
已知(x+y)2-2x-2y+1=0,則x+y=______.
數(shù)學(xué)人氣:461 ℃時(shí)間:2020-05-23 11:10:46
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