1 |
2 |
1 |
2 |
(2)假設(shè)當(dāng)n=k時(shí)等式成立,
即1?
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2k?1 |
1 |
2k |
1 |
k+1 |
1 |
k+2 |
1 |
2k |
則1?
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2k?1 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |
1 |
k+1 |
1 |
k+2 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |
1 |
k+2 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |
綜合(1)(2),等式對(duì)所有正整數(shù)都成立.
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2n?1 |
1 |
2n |
1 |
n+1 |
1 |
n+2 |
1 |
2n |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2k?1 |
1 |
2k |
1 |
k+1 |
1 |
k+2 |
1 |
2k |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2k?1 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |
1 |
k+1 |
1 |
k+2 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |
1 |
k+2 |
1 |
2k |
1 |
2k+1 |
1 |
2k+2 |