已知數(shù)列{an}的前n項(xiàng)和Sn=2n-1,則此數(shù)列奇數(shù)項(xiàng)的前n項(xiàng)和為( ?。?A.2n+1?13 B.2n+1?23 C.22n?13 D.22n?23
已知數(shù)列{an}的前n項(xiàng)和Sn=2n-1,則此數(shù)列奇數(shù)項(xiàng)的前n項(xiàng)和為( )
A.
B.
C.
D.
A.
2n+1?1 |
3 |
B.
2n+1?2 |
3 |
C.
22n?1 |
3 |
D.
22n?2 |
3 |
數(shù)學(xué)人氣:803 ℃時間:2019-12-24 15:23:08
優(yōu)質(zhì)解答
當(dāng)n=1時,a1=S1=21-1=1,當(dāng)n≥2時,an=Sn-Sn-1=2n-1-(2n-1-1)=2?2n-1-2n-1=2n-1,對n=1也適合∴an=2n-1,∴數(shù)列{an}是等比數(shù)列,此數(shù)列奇數(shù)項(xiàng)也構(gòu)成等比數(shù)列,且首項(xiàng)為1,公比為4.∴此數(shù)列奇數(shù)項(xiàng)的前n項(xiàng)和為1?(...
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