1
y=sin(1/2x+π/6)
x屬于[0,π/3]
π/6≤1/2x+π/6≤π/3
1/2 ≤ sin(1/2x+π/6) ≤ 根號(hào)3/2
值域【1/2,根號(hào)3/2】
2
y=-cos(3x-π/3)
x屬于[-π/3,π/3]
-π-π/3 ≤ 3x-π/3≤ π- π/3
(3x-π/3)的變化范圍涵蓋了從--π-π/3 到π- π/3正好2π的區(qū)間
∴y=-cos(3x-π/3)值域?yàn)椤?1,1】