若|x-1|+|y+3|=0,求1/(y-x-2)的值
x=1,y=-3,故1/(y-x-2)=1/（-3-1-2）=-1/6.
若|x-1|+|y+3|=0,求y-x-2分之1的值
若|x-1|+|y+3|=0,求y-x-2分之1的值
數(shù)學(xué)人氣：760 ℃時間：2020-05-14 09:52:06
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