=∫ x^(-5/2)dx
=-2/3∫dx^(-3/2)
=-2/3*x^(-3/2)+C∫(1-1/x²)*x^(3/4)dx
= ∫(x^2-1)/x^(5/4)dx
let x=t^4
求下列不定積分：∫dx/(x²√x)
求下列不定積分：∫dx/(x²√x)
數(shù)學(xué)人氣：636 ℃時(shí)間：2020-05-11 11:48:47
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