π |
3 |
2 |
π |
4 |
(1)函數(shù)f(x)的最小正周期為
2π |
2 |
(2)由題意知g(x)=f(x+
3π |
8 |
2 |
3π |
4 |
π |
4 |
2 |
∵0≤x≤π∴0≤2x≤2π
由g(x)在[0,π]上單調(diào)遞減
∴0≤2x≤
π |
2 |
3π |
2 |
∵0≤x≤
π |
4 |
3π |
4 |
故函數(shù)f(x)的單調(diào)遞減區(qū)間為[0,π]和[
3π |
4 |
π |
3 |
π |
3 |
m |
3π |
8 |
π |
3 |
2 |
π |
4 |
2π |
2 |
3π |
8 |
2 |
3π |
4 |
π |
4 |
2 |
π |
2 |
3π |
2 |
π |
4 |
3π |
4 |
3π |
4 |