P=ρ水gh=1×103kg/m3×9.8N/kg×0.15m=1.47×103Pa,
∵P=
F |
S |
∴水對(duì)容器底的壓力:
F=PS=1.47×103Pa×50×10-4m2=7.35N;
(2)水受到的重力:
G=mg=1kg×9.8N/kg=9.8N,
容器重忽略不計(jì),所以容器對(duì)桌面的壓力F′=G=9.8N,
容器對(duì)桌面的壓強(qiáng)P′=
F′ |
S |
9.8N |
50×10?4m2 |
答:(1)水對(duì)容器底的壓力是7.35N.
(2)桌面受到的壓強(qiáng)是1960N.