兩邊取自然對(duì)數(shù),有l(wèi)n y=（2e^-x）*ln x,對(duì)等式兩邊求導(dǎo),有y'/y=2((-e^-x)*ln x
+(e^-x)/x),所以f'（x）=y'=2((-e^-x)*ln x+(e^-x)/x)*y,即導(dǎo)數(shù)為2((-e^-x)*ln x+(e^-x)/x)*（x^2e^-x）
求函數(shù)f（x）=x^2e^-x的導(dǎo)數(shù)
求函數(shù)f（x）=x^2e^-x的導(dǎo)數(shù)
數(shù)學(xué)人氣：523 ℃時(shí)間：2020-05-05 13:10:52
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