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  • 若-3大于等于log2分之1x小于等于-2分之1,求f(x)=(log以2為底2分之x為對數(shù))乘(log以2為底4分之x)的最大值

    若-3大于等于log2分之1x小于等于-2分之1,求f(x)=(log以2為底2分之x為對數(shù))乘(log以2為底4分之x)的最大值
    和最小值
    數(shù)學人氣:283 ℃時間:2019-09-29 02:59:24
    優(yōu)質解答
    -3 ≤ log(1/2) x ≤ - 1/2
    log(1/2) x 單調減
    (1/2)^(-1/2) ≤ x ≤ (1/2)^(-3)
    x∈[根號2,8]
    f(x) = [log(2) (x/2)] * [ log(2) (x/4)]
    = [log(2) x - log(2) 2 ] * [ log(2) x - log(2) 4 ]
    = [log(2) x - 1 ] * [ log(2) x - 2 ]
    = [log(2) x]^2 - 3 log(2) x +2
    = [log(2) x - 3/2 ]^2 - 9/4 + 2
    = [log(2) x - 3/2 ]^2 - 1/4
    x=2^(3/2)=2根號2時有極小值
    最小值f(2根號2)= [log(2) 2根號2 - 3/2 ]^2 - 1/4 = (3/2-3/2)^2 - 1/4 = -1/4
    x∈[根號2,2根號2)時單調減;x∈[2根號2,8)時單調增
    f(根號2)= [log(2) 根號2 - 3/2 ]^2 - 1/4 = (1/2-3/2)^2-1/4 = 3/4
    f(8)= [log(2) 8 - 3/2 ]^2 - 1/4 = (3-3/2)^2-1/4 = 2
    ∴最大值f(x)max=f(8)=2
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