答：
利用分部積分法
∫ ln(x/2) dx
=xln(x/2) -∫ x d[ln(x/2)]
=xln(x/2)-∫ x*(2/x)*(1/2) dx
=xln(x/2)-x+C
∫ln(x/2)dx
∫ln(x/2)dx
數(shù)學(xué)人氣：940 ℃時間：2020-06-26 19:20:20
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