①當(dāng)直線(xiàn)CM與AB的斜率都存在時(shí),即x≠3,x≠0時(shí),則有kCMkAB=-1,
∴
y |
x?3 |
y |
x |
化簡(jiǎn)得x2+y2-3x=0(x≠3,x≠0),
②當(dāng)x=3時(shí),y=0,點(diǎn)(3,0)適合題意,
③當(dāng)x=0時(shí),y=0,點(diǎn)(0,0)不適合題意,
解方程組
|
5 |
3 |
2 |
3 |
5 |
∴點(diǎn)M的軌跡方程是x2+y2-3x=0(
5 |
3 |
y |
x?3 |
y |
x |
|
5 |
3 |
2 |
3 |
5 |
5 |
3 |