延長AM交BC于G,延長AN交BC于H.
因BE平分角ABC,AM⊥BE,
故AM=MG,
同理AN=NH,
∴MN‖GH,即MN‖BC.
BE,CE分別為△ABC中角ABC,角ACB的平分線,AM⊥BE于M,AN⊥CF于N,求證:MN‖BC
BE,CE分別為△ABC中角ABC,角ACB的平分線,AM⊥BE于M,AN⊥CF于N,求證:MN‖BC
是初二下冊練習(xí)冊82頁的拓展探究提.
是初二下冊練習(xí)冊82頁的拓展探究提.
數(shù)學(xué)人氣:380 ℃時(shí)間:2019-11-21 02:44:05
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