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  • 函數(shù)f(x)=2cos^2x+2sinxcosx,(1)求f(x)的最小正周期(2)記函數(shù)g(x)=f(x)*f(x+π/4),求函數(shù)g(x)的值域.

    函數(shù)f(x)=2cos^2x+2sinxcosx,(1)求f(x)的最小正周期(2)記函數(shù)g(x)=f(x)*f(x+π/4),求函數(shù)g(x)的值域.
    數(shù)學(xué)人氣:940 ℃時(shí)間:2020-03-23 01:11:51
    優(yōu)質(zhì)解答
    (1)f(x)=2cos²x+2sinxcosx
    =1+cos2x+sin2x
    =1+√2(√2/2cos2x+√2/2sin2x)
    =1+√2sin(2x+π/4)
    f(x)的最小正周期為:2π/2=π
    (2) g(x)=f(x)*f(x+π/4)
    =[1+√2sin(2x+π/4)][1+√2sin(2x+π/4+π/2)]
    =[1+√2sin(2x+π/4)][1-√2cos(2x+π/4)]
    =1+√2sin(2x+π/4)-√2cos(2x+π/4)-2sin(2x+π/4)cos(2x+π/4)
    =(sin(2x+π/4)-cos(2x+π/4))²+√2(sin(2x+π/4)-cos(2x+π/4))
    =(sin(2x+π/4)-cos(2x+π/4)+√2/2)²-1/2
    =(√2sin(2x+π/4-π/4)+√2/2)²-1/2
    =(√2sin(2x)+√2/2)²-1/2
    =2(sin(2x)+1/2)²-1/2
    當(dāng) -1≤sin2x≤1
    g(x)的值域?yàn)椋?1/2≤g(x)≤4
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