是不是應(yīng)該是4sinx開頭啊
要是的話
就是分子分母同時除以cosx 從而得到(4tanx-2)/(5+3tanx)=6/11 從而得tanx=2
(4tanx-2cosx)/(5cosx+3sinx)=6/11 求tanx,
(4tanx-2cosx)/(5cosx+3sinx)=6/11 求tanx,
數(shù)學(xué)人氣:736 ℃時間:2020-03-24 20:31:04
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