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  • 求一道數(shù)學(xué)題(應(yīng)該是相似的吧)

    求一道數(shù)學(xué)題(應(yīng)該是相似的吧)
    在三角形ABC中,∠A:∠B:∠C=1:2:4,
    求證:1/AB+1/AC=1/BC
    數(shù)學(xué)人氣:847 ℃時(shí)間:2020-05-21 02:41:19
    優(yōu)質(zhì)解答
    ∠A:∠B:∠C=1:2:4,
    A = π/7
    B = 2π/7
    C = 4π/7
    1/sinB + 1/sinC
    = (sinB+sinC)/(sinBsinC)
    = 4sin[(B+C)/2]cos[(B-C)/2]/[cos(B-C)-cos(B+C)]
    = 4sin(3π/7)cos(π/7)/[cos(2π/7)-cos(6π/7)]
    = 4sin(3π/7)cos(π/7)/[cos(2π/7)+cos(π/7)]
    = 2sin(3π/7)cos(π/7)/[cos(3π/14)cos(π/14)]
    = 2sin(3π/7)cos(π/7)/[cos((3π/14)sin(3π/7)]
    = 2cos(π/7)/[cos((3π/14)]
    = 2cos(π/7)sin(π/7)/[sin(π/7)cos(3π/14)]
    = sin(2π/7)/[sin(π/7)cos(3π/14)]
    = cos(3π/14)/[sin(π/7)cos(3π/14)]
    = 1/sin(π/7)
    = 1/sinA
    1/sinB +1/sinC = 1/sinA
    由正弦定理
    1/AB+1/AC=1/BC
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