f(x) = arctan [(x² - 2x - 3)/(x - 3)]1,定義域 x ≠32,間斷點 x = 33,有限漸進 x →3時,f(x) = arctan [(x² - 2x - 3)/(x - 3)] = arctan44,無限漸進 x →±∞時,f(x) = arctan [(x² - 2x - 3)/(x ...不好意思 我還有個問題,如果函數(shù)是 arctan((x^2-6x+8)/(x^2-2x-3))呢？arctan((x² - 6x + 8)/(x² - 2x - 3)) = arctan((x - 2)(x - 4)/[(x - 3)(x+1)]1，定義域 x ≠3并且 x ≠ -1 或者寫為：(-∞，-1) ∪ (-1，3) ∪ (3，∞) 2，間斷點 x = 3以及 x ≠ -13，有限漸進 x →3時， f(x) = arctan((x - 2)(x - 4)/[(x - 3)(x+1)] →-π/2 x →-1時，f(x) = arctan((x - 2)(x - 4)/[(x - 3)(x+1)] → π/24，無限漸進 x →±∞時，f(x) = arctan((x - 2)(x - 4)/[(x - 3)(x+1)]= arctan1 = π/45，相對最大值和（或）最小值 相對最大值x →- 1 時， f(x) = arctan = π/2x →2 時， f(x) = arctan = 0相對最小值x →0 時，f(x) = arctan= -8/3 x →3 時，f(x) = arctan= - π/26，絕對最大值和（或）最小值 π/2 ， -π/27，單調(diào)遞增和遞減區(qū)間遞增區(qū)間 = (-∞ ,-2)∪(0,1) ∪(3,∞)遞增區(qū)間 = (-1 ,0)∪(2,3)