x(x-1)-(x^2-y)=-2
x^2-x-x^2+y=-2
y-x=-2
(x^2+y^2)/2-xy
=(y^2-2xy+x^2)/2
=(y-x)^2/2
=(-2)^2/2
=2
(x-5y)^2-7(x-5y)-8
=[(x-5y)-8][(x-5y)+1]
=(x-5y-8)(x-5y+1)
x+y=1,xy=-1/2
x(x+y)(x-y）-x(x+y)^2
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2*(-1/2)*1
=1
第一步將輸入的兩個數(shù)分別進(jìn)行加,減,乘,平方和的運(yùn)算得到四個數(shù),第二步將所得的四個數(shù)相乘,第三步將所得的數(shù)輸出.
（1）如果輸入的兩個數(shù)分別為x,y,請將輸出的結(jié)果用x,y的多項(xiàng)式表示；
(x+y)(x-y)*(xy)*(x^2+y^2)
=xy(x^2-y^2)(x^2+y^2)
=xy(x^4-y^4)
=x^5y-xy^5
（2）如果輸入的兩個數(shù)分別為3,2,那么輸出的結(jié)果是多少?
(3+2)*(3-2)*(3*2)*(3^2+2^2)
=5*1*6*13
=390