①(a^2+1)-4a^2 =1-3a^2
② 12/(m^2-9)-2/m-3
=12/(m+3)(m-3)-2/m-3
=12-2m-6/(m+3)(m-3)
=-2/(m+3)
③這是一種題型
解題模式就是令x/2=y/3=z/5=k
得x=2k
y=3k
z=5k
代入第二個(gè)式子得k=2
x=4
y=6
z=10
幾道簡單的題、幫個(gè)忙唄、
幾道簡單的題、幫個(gè)忙唄、
(a^2+1)-4a^2 12/(m^2-9)-2/m-3
若x/2=y/3=z/5 且3x+2y-z=14,求x,y,z
(a^2+1)-4a^2 12/(m^2-9)-2/m-3
若x/2=y/3=z/5 且3x+2y-z=14,求x,y,z
數(shù)學(xué)人氣：164 ℃時(shí)間：2020-04-09 07:21:37
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