由題意得x^2/(x+2)=x-2+4/(x+2)=x+2+4/(x+2)-4
又令x+2=y
則原式為y+4/y-4
又令z=y+4/y,而此函數(shù)就是對勾函數(shù),可知兩個極點(diǎn)的坐標(biāo)為（2,4）;(-2,-4),此函數(shù)就可畫出
那么只要再向下移4個單位便是題目所求
二次有理分式函數(shù)怎么樣畫圖?x^2/(x+2)怎么畫,
二次有理分式函數(shù)怎么樣畫圖?x^2/(x+2)怎么畫,
數(shù)學(xué)人氣：158 ℃時間：2020-07-14 16:03:56
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