（a-2i)i = ai +2 = b-i
a = -1
b = 2
|z| = |-a-2i| = 根號5a=-1，b=2是怎么出來的ai +2 = b-i實部 b = 2虛部 a = -1那是怎么做出來的？ai +2 = b-i虛部和虛部相等ai = -i, a=-1實部和實部相等b=2
若（a-2i)i=b-i,其中a,b∈R,i是虛數(shù)單位,z=a+bi,則IzI(在為個z上面有一個一橫,是共軛復(fù)數(shù)）為?
若（a-2i)i=b-i,其中a,b∈R,i是虛數(shù)單位,z=a+bi,則IzI(在為個z上面有一個一橫,是共軛復(fù)數(shù)）為?
數(shù)學人氣：885 ℃時間：2020-01-28 05:20:32
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