實(shí)半軸a=1,b=1,c=√2,右焦點(diǎn)F2(√2,0),
直線方程:y/(x-√2)=√3,
y=√3x-√6,
代入雙曲線方程,2x^2-6√2x+7=0,
根據(jù)韋達(dá)定理,x1+x2=3√2,
x1*x2=7/2,
根據(jù)弦長公式,
|AB|=√(1+k^2)(x1-x2)^2
=√(1+k^2)[(x1+x2)^-4x1*x2]
=4.