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  • 因式分解的簡單應(yīng)用

    因式分解的簡單應(yīng)用
    (x^2y-xy^2)/(x-y)=______
    (a^2-9)/(a+3)=_____
    (m^2+2mn+n^2)/(m+n)=_____
    (4x^2-4x+1)/(1-2x)
    (a^2-64)/(a-8)
    (3x^3 y^2+6x^2 y^3)/(x+2y)
    (-9m^2+4n^2)/(3m+2n)
    (4a^2-20ab+25b^2)/(5b-2a)
    (1-16a^4)/(4a^2+1)/(2a+1)
    解方程
    x^2+2x=0
    9x^2-4=0
    -1/2x^2+2x=0
    (3a-4)^2=25
    數(shù)學(xué)人氣:959 ℃時間:2020-06-05 15:25:48
    優(yōu)質(zhì)解答
    x^2y-xy^2)/(x-y)=__xy(x-y)/(x-y)=xy____
    (a^2-9)/(a+3)=__=(a+3)(a-3)/(a+3)=a-3___
    (m^2+2mn+n^2)/(m+n)=__=(m+n)^2/(m+n)=m+n___
    (4x^2-4x+1)/(1-2x)=(1-2x)^2/(1-2x)=1-2x
    (a^2-64)/(a-8)=(a+8)(a-8)/(a-8)=a+8
    (3x^3 y^2+6x^2 y^3)/(x+2y)=3x^2y^2(x+2y)/(x+2y)=3x^2y^2
    (-9m^2+4n^2)/(3m+2n)=(2n+3m)(2n-3m)/(3m+2n)=2n-3m
    (4a^2-20ab+25b^2)/(5b-2a)=(5b-2a)^2/(5b-2a)=5b-2a
    (1-16a^4)/(4a^2+1)/(2a+1)=(1-4a^2)(1+4a^2)/[(4a^2+1)(2a+1)]=(1+2a)(1-2a)/(1+2a)=1-2a
    解方程
    x^2+2x=0
    x(x+2)=0
    x=0,x=-2
    9x^2-4=0
    (3x+2)(3x-2)=0
    x=-2/3,x=-2/3
    -1/2x^2+2x=0
    -1/2x(x-4)=0
    x=0,x=4
    (3a-4)^2=25
    (3a-4)^2-25=0
    (3a-4+5)(3a-4-5)=0
    (3a-1)(3a-9)=0
    a=1/3,a=3
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