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  • 解分式方程:(1)1/(x+6)+1/(x+4)=1/(x+7)+1/(x+3);(2)1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).

    解分式方程:(1)1/(x+6)+1/(x+4)=1/(x+7)+1/(x+3);(2)1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
    數(shù)學(xué)人氣:545 ℃時(shí)間:2020-03-25 21:11:11
    優(yōu)質(zhì)解答
    1)設(shè)x+5=y1/(y+1)+1/(y-1)=1/(y+2)+1/(y-2)2y/(y+1)(y-1)=2y/(y+2)(y-2)y(y+2)(y-2)=y(y+1)(y-1)y(y^2-4)=y(y^2-1)y=0x+5=0x=-52)設(shè)x-5=y1/(y+2)+1/(y-2)=1/(y+1)+1/(y-1)2y/(y+2)(y-2)=2y/(y+1)(y-1)y(y+1)(y-1)=y...不是這樣算的吧,(1)應(yīng)該化成:1/(x+6)+1/(x+7)=1/(x+4)+1/(x+3)(2)應(yīng)該化成:1/(x-3)+1/(x-4)=1/(x-7)+1/(x-6)你可以試試,沒我的算法簡單呦
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