(1/2)橢圓ax^2+bx^2=1與直線x+y－1＝0相交于A,B兩點(diǎn),C是AB的中點(diǎn),若|AB|=2倍根號(hào)2,OC的斜率為根號(hào)2/...
(1/2)橢圓ax^2+bx^2=1與直線x+y－1＝0相交于A,B兩點(diǎn),C是AB的中點(diǎn),若|AB|=2倍根號(hào)2,OC的斜率為根號(hào)2/...
(1/2)橢圓ax^2+bx^2=1與直線x+y－1＝0相交于A,B兩點(diǎn),C是AB的中點(diǎn),若|AB|=2倍根號(hào)2,OC的斜率為根號(hào)2/2,求橢圓
(1/2)橢圓ax^2+bx^2=1與直線x+y－1＝0相交于A,B兩點(diǎn),C是AB的中點(diǎn),若|AB|=2倍根號(hào)2,OC的斜率為根號(hào)2/2,求橢圓
數(shù)學(xué)人氣：899 ℃時(shí)間：2019-11-25 22:23:34
優(yōu)質(zhì)解答
A（x1,y1）B（x2,y2）a(x1-x2)(x1+x2)+b(y1-y2)(y1+y2)=0,(y1-y2)/(x1-x2)= -1(y1+y2)/(x1+x2)=√2/2,a√2=b|AB|=2√2=√[(x1+x2)^2-4x1x2]√2a=(2+√2)/2,b=1+√2方程[(2+√2)/2]x^2+(1+√2)y^2=1
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