z=f(x+y,x-y),則dz=?
z=f(x+y,x-y),則dz=?
數(shù)學(xué)人氣：909 ℃時(shí)間：2020-06-16 11:03:42
優(yōu)質(zhì)解答
dz=f1d(x+y)+f2d(x-y)=f1(dx+dy)+f2(dx-dy)=(f1+f2)dx+(f1-f2)dy.f1,f2代表二元函數(shù)f對(duì)其兩個(gè)自變量的偏導(dǎo)數(shù).
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