y=(x²+2x+3)/(x²+1)=1+2(x+1)/(x²+1)
求導(dǎo)可得y'=-2(x²+2x-1)/(x²+1)²
令y'=0可得x=√2-1或-√2-1
lim(x→∞)(x²+2x+3)/(x²+1)=1
當(dāng)x=√2-1時(shí)y=(3√2+6)/4取得最大值
當(dāng)x=-√2-1時(shí)y=(6-3√2)/4取得最小值
∴y=(x²+2x+3)/(x²+1)的值域?yàn)閇(6-3√2)/4,(3√2+6)/4]