x/(x-2)-2=m^2/(x-3)(4-x)/(x-2)=m^2/(x-3)(4-x)(x-3)/(x-2)(x-3)=m^2(x-2)/(x-3)(x-2)[x^2-(7-m^2)x+12-2m]/((x-3)(x-2)=0方程無解,則：x=2或x=3當x=2時,x^2-(7-m^2)x+12-2m=0 m無解當x=3時,x^2-(7-m^2)x+12-2m=0 m...第三步應該怎么轉(zhuǎn)成第四步阿(4-x)(x-3)/(x-2)(x-3)=m^2(x-2)/(x-3)(x-2)[x^2-(7-m^2)x+12-2m]/((x-3)(x-2)=0你是說這一步嗎？通分后，再將分子(4-x)(x-3)相乘，并合并同類項然后移項，全部移動到等號右邊[x^2-(7-m^2)x+12-2m]/((x-3)(x-2)=0 第二個M應該要有個平方吧當x=2時，x^2-(7-m^2)x+12-2m^2=0m無解當x=3時，x^2-(7-m^2)x+12-2m^2=0m=0∴m=0