分析：根據(jù)題意,a是函數(shù) f(x)=x3-log1/2x的零點,函數(shù) f(x)=x3-log1/2x是增函數(shù),本題根據(jù)函數(shù)的單調(diào)性和零點的性質(zhì)進(jìn)行求解．∵函數(shù) f(x)=x3-log1/2x在（0,+∞）上是增函數(shù),
a是函數(shù) 函數(shù) f(x)=x3-log1/2x的零點,即f（a）=0,
∴當(dāng)0＜x0＜a時,f（x0）＜0,
故答案為：＜．點評：本題主要考查了函數(shù)零點的判定定理,函數(shù) f(x)=x3-log12x是增函數(shù),單調(diào)函數(shù)最多只有一個零點,是解題的關(guān)鍵．嗯