過(guò)拋物線y=ax^2(a>0)的焦點(diǎn)F作直線交拋物線于P、Q兩點(diǎn),若線段PF與QF的長(zhǎng)分別為p、q,則1/p+1/q=?
過(guò)拋物線y=ax^2(a>0)的焦點(diǎn)F作直線交拋物線于P、Q兩點(diǎn),若線段PF與QF的長(zhǎng)分別為p、q,則1/p+1/q=?
高手請(qǐng)進(jìn)!注意焦點(diǎn)是(0,1/4a)!
高手請(qǐng)進(jìn)!注意焦點(diǎn)是(0,1/4a)!
數(shù)學(xué)人氣:859 ℃時(shí)間:2019-10-17 05:50:52
優(yōu)質(zhì)解答
答:1/p+1/q=4a(可用特值y=1/4a 計(jì)算).下面用一般方法:設(shè)斜率為k,直線方程為y=kx+1/4a,P(x1,y1),Q(x2,y2),由第二定義有y1=p-1/4a,y2=q-1/4a,又P、Q都在直線上,得到p=kx1+1/2a,q=kx2+1/2a.又P、Q是直線和曲線的交...
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